Math, asked by xtremegaming2818, 3 months ago

if the hcf and lcm of two positive integers a and b are x and y respectively then x2y2/a2b2

Answers

Answered by spiderman2019

4

Answer:

Step-by-step explanation:

The product of two numbers = HCF * LCM

=> ab = xy

=> xy/ab = 1

Thus x²y²/a²b² = (xy/ab)² = 1² = 1.

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