Question

If the HCF of 210 & 55 is expressible in form of 210*5 +55y. Find the value of y.

Answer 1

f the HCF of 210 & 55 is expressible in form of 210*5 +55y. Find the value of y.

Good question,

Here is your perfect answer!

To find HCF :

=) 210 = 55*3 + 45,

=) 55 = 45*1 + 10

=) 45 = 10*4 + 5

=) 10 = 5*2 + 0

Hence 5 is the HCF.

=) 5 = 210*5 + 55y

=) 5 - 1050 = 55y

=) - 1045/55 = y

=) y = - 19.

Answer 2

heyaa!!!!

here is the answer..PLZ MARK AS BRAINLIEST!!

Let us first find the HCF of 210 and 55.

Applying Euclid division lemna on 210 and 55, we get

210 = 55 × 3 + 45

55 = 45 × 1 + 10  

45 = 4 × 10 + 5  

10 = 5 × 2 + 0  

We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55.

∴ 5 = 210 × 5 + 55y

⇒ 55y = 5 - 1050 = -1045

∴ y = -19