If the HCF of 210 and 55 is expressible in the form 210*5+55y, find y.
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Answered by
48
HCF of 210 & 55 is 5
210*5 + 55y = 5
1050 + 55y = 5
55y = -1045
y = -19
210*5 + 55y = 5
1050 + 55y = 5
55y = -1045
y = -19
srishtu:
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Answered by
9
the hcf will be 5
210*5 + 55y = 5
55y = -1045
y = -19
210*5 + 55y = 5
55y = -1045
y = -19
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