if the HCF of 210 and 55 is expressible in the form 210 x 5 + 55y then find y.
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Hi there!
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HCF OF 210 & 55 :
210 = 55 × 3 + 45
55 = 45 × 1 + 10
45 = 10 × 4 + 5
10 = 5 × 2 + 0
■ Therefore, HCF = 5
Now, 5 = 210 × 5 + 55y
》 5 / 5 = 210 + 55y
》 1 - 210 = 55y
》 209 / 55 = y
■ Ans. y = 3.8
____________________________
I hope this helps.
____________________________
HCF OF 210 & 55 :
210 = 55 × 3 + 45
55 = 45 × 1 + 10
45 = 10 × 4 + 5
10 = 5 × 2 + 0
■ Therefore, HCF = 5
Now, 5 = 210 × 5 + 55y
》 5 / 5 = 210 + 55y
》 1 - 210 = 55y
》 209 / 55 = y
■ Ans. y = 3.8
____________________________
I hope this helps.
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