If the HCF of 210 and 55 is expressible in the form of 210×5+55y find y
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5
Answer:
-19
Step-by-step explanation:
By Euclid's division algorithm
210 = 55 × 3 + 45
55= 45 × 1 + 10
45= 10 × 4 + 5
10= 5 × 2 + 0
HCF(210,55) = 5
5 = 210 × 5 + 55y
5 - 1050 = 55y
-1045 = 55y
y = -1045/55
y = -19
ds269729:
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