if the HCF of 210 and 55 is expressible in the form of 210 * 5 + 55 y find you ?????
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HCF of { 210, 55 }
factor of 210 = 2 × 3 × 5 × 7
factors of 55 = 5 × 11
common factor of {210, 55 } = 5
so, HCF of {210, 55 } = 5
now,
210× 5 + 55 y = 5
55y = 5 -1050 = -1045
y = -1045/55= -95/5 = -19
factor of 210 = 2 × 3 × 5 × 7
factors of 55 = 5 × 11
common factor of {210, 55 } = 5
so, HCF of {210, 55 } = 5
now,
210× 5 + 55 y = 5
55y = 5 -1050 = -1045
y = -1045/55= -95/5 = -19
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