If the HCF of 210 and 55 is expressible in the from 210×5+55y find y
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210*5= 1050
1050+55y=5(HCF)
55y= -1045
y =- 1045/55== -209/11== -19
y=. -19
210*5= 1050
1050+55y=5(HCF)
55y= -1045
y =- 1045/55== -209/11== -19
y=. -19
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