If the HCF of 210 and 55 is the expressible in the form of 210x+55y , find x and y
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210x + 55y = hcf (210, 55) = 5
{210 = 55×3 + 45
55 = 45×1 + 10
45 = 10×4 + 5
10 = 5×2 + 0}
5 = 45 - 10×4
= 45 - (55 - 45×1)×4
= 45×5 - 55×4
= (210 - 55×3)×5 - 55×4
= 210×5 + 55×(-19)
Thus, x = 5, y = -19.
{210 = 55×3 + 45
55 = 45×1 + 10
45 = 10×4 + 5
10 = 5×2 + 0}
5 = 45 - 10×4
= 45 - (55 - 45×1)×4
= 45×5 - 55×4
= (210 - 55×3)×5 - 55×4
= 210×5 + 55×(-19)
Thus, x = 5, y = -19.
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