Math, asked by anne7113, 1 year ago

If the hcf of 408 and 1032 is expressible in the form of 1032m 408n find m and n

Answers

Answered by GauravSaxena01

Answer:

If the HCF of 408 and 1032 will be written as

By geometrician 's division rule,

1032 = 408×2 + 216

408 = 216×1 + 192

216 = 192×1 +24

192 = 24×8 + 0

Since the rest becomes 0 here,

thus HCF of 408 and 1032 is 24

Now,

1032x - 408 ×5 = HCF of those numbers

=> 1032x - 2040 = 24

=> 1032x = 24+2040

=> x= $\frac{2064}{1032}$

=> x = 2 So worth of x is 2.

===============

@GauravSaxena01

rohitkadyan6218: It is wrong as you have not done it according to the statement of question you are taking the value of n =5 which is not given. If you have any other reason for this than tell

Answered by jnvpintu1706

Answer:

Step-by-step explanation:

Attachments:

Previous Question

Next Question