If the hcf of 408 and 1032 is expressible in the form of 1032m 408n find m and n
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If the HCF of 408 and 1032 will be written as
By geometrician 's division rule,
1032 = 408×2 + 216
408 = 216×1 + 192
216 = 192×1 +24
192 = 24×8 + 0
Since the rest becomes 0 here,
thus HCF of 408 and 1032 is 24
Now,
1032x - 408 ×5 = HCF of those numbers
=> 1032x - 2040 = 24
=> 1032x = 24+2040
=> x=
=> x = 2 So worth of x is 2.
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@GauravSaxena01
rohitkadyan6218:
It is wrong as you have not done it according to the statement of question you are taking the value of n =5 which is not given. If you have any other reason for this than tell
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