Question

If the HCF of 56 and 72 is expressible in the form of 56a +72 *53 then find the value of a

Answer 1

Hii friend,

Prime factorisation of 56 = 2 × 2 × 2 × 7

Prime factorisation of 72 = 2 × 2 × 2 × 2 × 3 × 3

HCF of 56 and 72 = 2 × 2 × 2 = 8

According to question,

HCF of 56 and 72 = 56A + 72 × 53


8 = 56A +72 × 53

56A = 8 - 3816

56A = -3808

A = -3808/56

A = -68 .

Hence,

The Value of A is -68

HOPE IT WILL HELP YOU.... :-)

Answer 2

Answer:

Step-by-step explanation:

Since, Prime factorization of 56 is=2×2×2×7 and prime factorization of 72 is=2×2×2×2×3×3.

Then, HCF of 56 and 72 is=2×2×2=8 .

Now, the HCF of 56 and 72 is expressible in the form of $56a+72{\times}53$, then

8=$56a+72{\times}53$

$8=56a+3816$

$56a=-3808$

$a=-68$

Thus, the value of a will be =-68.