Question

If the HCF of 65 and 117 can be expressible in the form 65n-117, then find the value of n.

Answer 1

65= 5×13

117= 3×3×13

HCF= 13

NOW,

HCF= 65n- 117

13= 65n- 117

65n= 13+ 117

$n= \frac{130}{65}$

n= 2

HENCE THE VALUE OF n= 2.

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