Question

If the HCF of 65 and 117 is expressible in the form 65m - 117, then the value of 'm' is​

Answer 1

Answer:

First, find the HCF of 65 and 117

117 = 65 x 1 +52

65 = 52 x 1 + 13

52 = 13 x 4 + 0 (zero remainder)

Therefore, HCF (117, 65) is 13

Now,

➜ 65 m - 117 = 13

⇒ 65 m = 13 + 117

⇒65 m = 130

⇒ m = 2

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Answer 2

Answer:

2

Explanation:

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