If the hcf of 65 and 117 is expressible in the form 65m-117then find the value of 'm'
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HCF of 65 and 117 is 13.
65m-117=13
65m=13+117
65m=130
m=130/65=2
65m-117=13
65m=13+117
65m=130
m=130/65=2
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Answered by
1
hcf of 65 and 117 is 13.
then
it is mentioned hcf =65m-117
so
65m-117=13
65m=130
m=130/65
m=2
then
it is mentioned hcf =65m-117
so
65m-117=13
65m=130
m=130/65
m=2
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