if the height and area of a Trapezium are 11 decameter and 396 deca metre square and the parallel sides are in the ratio 3 is to 5 find their lengths
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h/2(a +b) is the formula
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area of trapezium= 1/2 × height×{ sum of parallel sides}
396= 1/2× 11×{3x+5 x}
396=1/2×11×8x
396=1×11×4x
396=44x
x= 9
ans.the lengths are-
3x= 3×9=27
5x=5×9=45
396= 1/2× 11×{3x+5 x}
396=1/2×11×8x
396=1×11×4x
396=44x
x= 9
ans.the lengths are-
3x= 3×9=27
5x=5×9=45
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