Question

if the height and sum of the parallel sides of a trapezium are increased three times, then find the increase percent of area​

Answer 1

Answer:

800%

Step-by-step explanation:

area of trapezium is a is equal to a plus b / 2 multiplying by height.

1. a and b are the sides of it...

all are increasing by three times then area 3a plus 3b by 2 multiplying by 3height then new area is 9 times of first are

then increasment is 8 times of first area then increase percentage is 800%