if the height and sum of the parallel sides of a trapezium are increased three times, then find the increase percent of area
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Answer:
800%
Step-by-step explanation:
area of trapezium is a is equal to a plus b / 2 multiplying by height.
- a and b are the sides of it...
all are increasing by three times then area 3a plus 3b by 2 multiplying by 3height then new area is 9 times of first are
then increasment is 8 times of first area then increase percentage is 800%
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