if the height of a tree is 5m and a man stand 5m away from its foot .The angle of elevation of the top of tree is
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Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B. Hence, the total height of the tree(A'B) = A'C + CB = 13 + 5 = 18 m.
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