Question

if the height of a tringles is decreased by 10% and base is increased by 20% .what will be the effect on its area

Answer 1

Answer:

The area will be 1.08th of the original

Step-by-step explanation:

Initial area = (1/2) * base * height = bh/2

height after decrement = (h) - $\frac{10h}{100}$ =  h - $\frac{h}{10}$ = $\frac{9h}{10}$

base after increment = $b + \frac{20b}{100} = b + \frac{2b}{10} = \frac{12b}{10}$

Area after changes = $\frac{1}{2} * \frac{9h}{10} * \frac{12b}{10} = \frac{9h}{10} * \frac{6b}{10}$

                                = $\frac{54bh}{100}$ = 0.54bh

Comparision = $\frac{0.54bh}{bh/2}$ = 1.08

So the area will increase by 1.08 times.

HOPE IT HELPS !!