if the height of the traiangle is 10root3 cm. find the area of the traingle
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Step-by-step explanation:
Let ABC is an equilateral ∆ in which AB=BC=CA= x(let) and height AD=10√3
units.
In right ∆ ADC , AD/AC = sin60°
(10√3)/x = √3/2 or x = 20units.
Area of equilateral ∆ = (√3/4)•side^2
=√3×400/4sq.units
=100√3 = 100×1.732 = 173.2 sq.units. Answer.
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