If the height of the triangle is decreased by 40 percent and its base is increased by 40 percent what will be the change in its area
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Let height and base of the triangle be xx and yy units respectively.
4040% of x=2x5x=2x5
4040% of y=2y5y=2y5
Now since xx is decreased and yy is increased, let
x′=x−2x5x′=x−2x5
=3x5=3x5
y′=y+2y5y′=y+2y5
=7y5=7y5
Therefore the new height is 3x53x5 and the new base is 7y57y5.
Let A=xy2A=xy2 and A′=3x5×7x52A′=3x5×7x52
Dividing AA by A′A′, we get 25212521. Let the areas be 2525unitunit22 and 2121unitunit22.
Percent change =100(final−initial)intial=100(final−initial)intial
Therefore percent change in area
=100(21−25)25=100(21−25)25
−16%
Therefore area decreases by 16%.
4040% of x=2x5x=2x5
4040% of y=2y5y=2y5
Now since xx is decreased and yy is increased, let
x′=x−2x5x′=x−2x5
=3x5=3x5
y′=y+2y5y′=y+2y5
=7y5=7y5
Therefore the new height is 3x53x5 and the new base is 7y57y5.
Let A=xy2A=xy2 and A′=3x5×7x52A′=3x5×7x52
Dividing AA by A′A′, we get 25212521. Let the areas be 2525unitunit22 and 2121unitunit22.
Percent change =100(final−initial)intial=100(final−initial)intial
Therefore percent change in area
=100(21−25)25=100(21−25)25
−16%
Therefore area decreases by 16%.
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