if thequadratic equationax^2-4ax+2a+1=0 has repeated roots,a=....
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Hope this helps you.
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Pls mark as brainliest. :)
Pranjal01:
Sry ,the picture didn't upload I think.
Here's your answer -->
If the equation has equal roots,then the discriminant (D) must be=0
ie. D=0
=>b^2-4ac=0
16a^2-8a-8=0
8[2a^2-a-1=0]
2a^2-2a+a-1=0
2a(a-1)+1(a-1)=0
(2a+1)(a-1)=0
If 2a+1=0
=>a=-1/2
If a-1=0
=>a=1
Hope this helps you.
Pls mark as brainliest. :)
If the equation has equal roots,then the discriminant (D) must be=0
ie. D=0
=>b^2-4ac=0
16a^2-8a-8=0
8[2a^2-a-1=0]
2a^2-2a+a-1=0
2a(a-1)+1(a-1)=0
(2a+1)(a-1)=0
If 2a+1=0
=>a=-1/2
If a-1=0
=>a=1
Hope this helps you.
Pls mark as brainliest. :)
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