If the hight of the cylinder becomes 1/4 of the orginal hight and the radius is doubled ,then the curved surface area of the new cylinder is equal to how many times the orginal cylinder.
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Volume of the cylinder will remain unchanged. We know that, the volume of a cylinder having base radius r and height h is V = πr
2
h
Now, if the radius is doubled (r=2r) and the new height is
1/4
th
of the original height (h=
4
1
h )
So, the new volume would be=
V= π(2r)
2
×
4
1
h = π(2r)
2
h=V
Hence, the new volume of cylinder is same as the original volume.
2
h
Now, if the radius is doubled (r=2r) and the new height is
1/4
th
of the original height (h=
4
1
h )
So, the new volume would be=
V= π(2r)
2
×
4
1
h = π(2r)
2
h=V
Hence, the new volume of cylinder is same as the original volume.
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