Math, asked by rishavagaming, 1 year ago

If the image of the point(-1,2) in the line 4x+3y-p = 0 is the point (3,5), then find the value of p.

Answers

Answered by knjroopa
5

Answer:

- 45

Step-by-step explanation:

Given If the image of the point(-1,2) in the line 4x+3y-p = 0 is the point (3,5), then find the value of p.

We know that (x,y) = ax + by + c = 0

x – x1 / a = y – y1/b = - 2(ax1 + by1 + c) / a^2 + b^2

3 + 1 / 4 = 5 – 2/3 = - 2(4(1) + 3(2) + p) / 4^2 + 3^2

4/4 = 3/3 = -2(4 + 6 + p)/16 + 9

1 = 1 = -2(10 + p) / 25  

-20 – p = 25

P = - 45

Answered by xyz222333
7

Step-by-step explanation:

Solution.....,.,,.,.,.,.,.,.,.,.,.,.,.,.

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