If the image of the point(-1,2) in the line 4x+3y-p = 0 is the point (3,5), then find the value of p.
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Answered by
5
Answer:
- 45
Step-by-step explanation:
Given If the image of the point(-1,2) in the line 4x+3y-p = 0 is the point (3,5), then find the value of p.
We know that (x,y) = ax + by + c = 0
x – x1 / a = y – y1/b = - 2(ax1 + by1 + c) / a^2 + b^2
3 + 1 / 4 = 5 – 2/3 = - 2(4(1) + 3(2) + p) / 4^2 + 3^2
4/4 = 3/3 = -2(4 + 6 + p)/16 + 9
1 = 1 = -2(10 + p) / 25
-20 – p = 25
P = - 45
Answered by
7
Step-by-step explanation:
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