Question

solve:
$4 \sqrt{3 \: } x {}^{2} + 5x \: - 2 \sqrt{3 } = 0$
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Answer 1

$\huge{{\huge{\boxed{\huge{\red\star\mathfrak\purple{\large{\underline{\underline{ Answer! }}}}}}}}}$

$\bold{4 \sqrt{3 \: } x {}^{2} + 5x \: - 2 \sqrt{3 } = 0 \: }$

We, need to do middle term splitting, in this case

$\implies \bold{ 4 \sqrt{3} x {}^{2} + 8x - 3x - 2 \sqrt{3} = 0}$

$\implies \bold{ 4x( \sqrt{3} x + 2) - \sqrt{3} ( \sqrt{3} x + 2 ) = 0}$

$\implies \bold{ (4x - \sqrt{3} )( \sqrt{3}x + 2 ) = 0}$

Therefore,

$\bold{4x - \sqrt{3} = 0}$

$\implies \bold{4x = \sqrt{3} }$

$\implies \bold{x = \frac{ \sqrt{3} }{4} } \:$

also,

$\bold{ \sqrt{3} x + 2 = 0}$

$\bold{ \implies \sqrt{3} x = - 2}$

$\bold{ \implies \: x = \frac{ - 2}{ \sqrt{3} } }$

The values of x are $\bold{ \frac{ \sqrt{3} }{4} \: \: and \: \: \frac{ - 2}{ \sqrt{3} } }$

Answer 2

$\huge\underline\textbf{Answer:-}$

I hope my answer in the attachment will help you

_Alone_

=>ItsDevil'sKing