Question

. If the incident energy is is 200 cal, absorptive power is 0.31 and reflection coefficient is 0.41 then the amount of energy transmitted will be

Answer 1

given : If the incident energy is is 200 cal, absorptive power is 0.31 and reflection coefficient is 0.41.

To find : The amount of energy transmitted

solution : first find coefficient of transmittance.

we know, r + a + t = 1

here, coefficient of reflection, r = 0.41

coefficient of absorption, a = 0.31

so, 0.41 + 0.31 + t = 1

⇒t = 1 - (0.41 + 0.31) = 0.28

Now amount of energy transmitted = incident energy × coefficient of transmittance

= 200 Cal × 0.28

= 56 Cal

Therefore the amount of energy transmitted will be 56 Cal.