if the increase in the kinetic energy of a body is 22% then what is the momentum ofabody
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When kinetic energy of body is increased by 300 % momentum of body is increased by
(a)200%(b)100%(c)50%(d)150%
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A)
P1,P2 momentum before and after let orginal K.E be 100 J
K.E increased by 300%
new KE=400J
P22P12=E2E1=400100=4
P2P1=2=>P2=2P1
Increase % =P2−P1P1×100
=2P1−P1P1×100
=100%
Hence b is the correct answer
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