Question

If the initial moles of a,b,c and d are 0.5,1,0.5 and 3.5 moles respectively in one litre vessel. what is the equilibrium concentration of b

Answer 1

Kc = [c][d]/[a][b]^2 Now, as volume is 1 ltr, Molarity = No. of moles So, [b]^2= [c][d]/[a]Kc = (3.5 x 0.5 / 0.5) x 10^-9 Hence, [b] = (35 x 10^-10) ^ 0.5 = 5.91 x 10^-5 M