Question

if the instantaneous velocity if a particle moving in a circle drawn on XY plane is vector v=(2m/s)Î-(2m/s)j,through which quadrant is the particle movingat the instant if it is travelling (a)clockwise, (b)counterclockwise around the circle? for both cases give the fig.of vector v......plz tell fast....

Answer 1

In both cases the components will have the same value.

Explanation:

(a) Clockwise

• When the instantaneous velocity is clockwise, the particle would be travelling through the first quadrant.
• In this case the components of the velocity are Vx and Vy respectively.
• In the first quadrant Vx will be positive and Vy will be negative.

(b) Anti-clockwise

• When the instantaneous velocity is anticlockwise, the particle would be travelling through the third quadrant.
• The components of the velocity are Vx and Vy respectively.
• In the third quadrant vx will be positive and vy will be negative.

Thus in both cases the components will have the same value.

Also learn more

One of the rectangular components of a velocity of 20 ms is 10ms. find other component ?

https://brainly.in/question/4785882