Math, asked by anuraina, 9 months ago

If the interest on Rs 200 be Rs 25 in a certain time, what will be the interest on Rs 750 for the same time.

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Answers

Answered by neeraj77747

Answer:

Since nothing is mentioned whether the question is of simple interest or compound interest, I would like to tell the approach in general and solve it via simple interest.

Simple Interest=p*r*t/100

Given 25=200*r*t/100

This gives r*t/100=25/200=1/8

Now for p=750

SI= p*r*t/100= 750*1/8

=Rs. 93.75

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Answered by Mihir1001

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$Answer:$

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$\huge\boxed{\fcolorbox{red}{#ffdfff}{Rs. 93.75}}$

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$Step-by-step-explaination:$

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first amount = ₹200

first interest = ₹25

Therefore,

interest rate

$= \frac{25}{200} \times 100 \: \%$

$= 12.5\%$

Now,

new amount = ₹750

Hence,

new interest

$= 12.5\% \: of \: 750$

$= \frac{12.5}{100} \times 750$

$= \frac{125}{100 \times 10} \times 75 \times 10$

$= \frac{125}{100} \times 75$

$= \frac{25 \times 5}{25 \times 4} \times 25 \times 3$

$= \frac{125}{4} \times 3$

$= \frac{375}{4}$

$=$ ₹ $\: 93.75$

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