Question

If the internal and external diameter of a hollow hemispherical vessel are 42cm and 45.5cm then it's outer curved surface area is

Answer 1

Given Internal hollow hemispherical vessel r1 = 42cm. Then radius r = d/2 = 21.

Given External hollow hemispherical vessel r2 = 45.5cm. radius r = 22.75.

Capacity of hollow hemispherical vessel = 2/3 pir1^3

                                                                    = 2/3 * 22/7 * (21)^3

                                                                    = 2 * 22 * 21 * 21

                                                                   = 19.404 litres.

Outer's surface area = 2pir2^2

                                   = 2 * 22/7 * (22.75)^2

                                   = 3253.25 cm^3.


Hope this helps! :)

Answer 2

Answer:

GIVEN :-

❥ Internal radius of a hollow hemispherical vessel (${r}_{1}$) = $\frac{d}{2}$

• $\frac{ 42 }{ 2 }$
• 21 cm

❥ External radius of a hollow hemispherical vessel (${r}_{2}$) = $\frac{ d }{ 2 }$

• $\frac{ 45.5 }{ 2 }$
• 22.75 cm

Step-by-step explanation:

Capacity of a hollow hemispherical vessel = ⅔π${r}_{1}$³

• ⅔ × $\frac{22}{7}$ × 21 × 21 × 21
• 19404 cm³
• 19.404 litres

Curved surface area of a hollow hemispherical vessel = 2π${r}_{2}$³

• 2 × $\frac{ 22 }{ 7 }$ × (22.75) ²
• 3253.25 cm³

Therefore, the outer curved surface area of a hollow hemispherical vessel is 3253.25 cm³