Question

If the kinetic energy of a body increased by 300% by what percentage will the linear momentum increase

Answer 1

Answer:

It increases by

Explanation:

K= 1/2mv²= p²/2m

p=√2km

If k e is increased by 300%,

New k e= 4k e

Thus momentum becomes 2wice. So it increases 200%

Btw are u in Aps Kolkata? We had the same question in our paper recently.

Answer 2

Explanation:

let the initial kinetic energy be k

and initial momentum be p

we know that

$k = \frac{1}{2} m {v}^{2}$

and p=mv

so

$k = \frac{ {p}^{2} }{2m}$

$p = \sqrt{2mk}$

final kinetic energy is increased by 300%

so final kinetic energy = 4k

Final momentum =

$\sqrt{2m \times 4k}$

final momentum =

$2 \sqrt{2mk}$

final momentum =2p

increase in momentum= 2p-p =p

% increase in momentum = (change in momentum/initial momentum)*100

% Change in momentum=(p/p)*100

= 100%