If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is:
Answers
Answered by
6
the percentage change in the de-Broglie wavelength of the particle is 75% .
Answered by
5
Answer:
75%
Explanation:
Increase in kinetic energy of particle = 16 times (Given)
De - Broglie wavelength is a wavelength, that determines the probability density of finding any object at a given point of the total configuration space.
According to the equation -
λ = √h2mk
λ1 = √h2m × 16k
λ = λ4
Thus, the percentage change in the de- Broglie wave length -
= λ−λ1/λ ×100 = (1−λ1/λ) ×100
= (1−1/4) × 100
=75%
Thus, the percentage change in the de-Broglie wavelength of the particle is 75%.
Similar questions