Question

If the L.C.M of two numbers is 144 and their H.C.F is 24 such that one of the numbers is 48, then,the other number is

Answer 1

Question :-

If the L.C.M of two numbers is 144 and their H.C.F is 24 such that one of the numbers is 48, then,the other number is ?

Solution :-

we know That :-

=> The product of LCM and HCF of any two given natural numbers is equivalent to the product of the given numbers.

we have given That :-

→ LCM of Two Numbers = 144.

→ HCF of Two Numbers = 24.

→ One Number = 48.

Putting values we get :-

→ LCM * HCF = One Number * Other Number

→ 144 * 24 = 48 * Other Number

→ Other Number = (144*24)/48

→ Other Number = 72.

Hence, The Other Number is 72.

Answer 2

Given:-

LCM(a, 48)=144

HCF(a, 48)=24

$\rule{200}{1}$

To Find:-

→The Other no?

$\rule{200}{1}$

AnswEr:-

♦Using Forumla♦

→LCM×HCF(a,b)=product of no.s[a,b]

•Putting the Values•

→144×24=a×48

★Moving 48 to LHS★

→$\frac{144×24}{48}$=a

→$\frac{ \cancel{144}× \cancel{24}}{\cancel{48}}$

→72=a

๛Hence the Other no. is 72๛

$\rule{200}{2}$