Question

If the last term is 232 d=4,a=4 find the values of n and also S7​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

S  

n

​  

=  

2

n

​  

{2a+(n−1)d}

a+(n−1)d=31⇒a=31−4(n−1)

∴136=  

2

n

​  

{2[31−4(n−1)]+(n−1)d}

n[70−8n+4n−4]=272

n(66−4n)=272

4n  

2

−66n+272=0

2n  

2

−33n+136=0

2n(n−8)−17(n−8)=0

(2n−17)(n−8)=0

∴n=8

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Answer 2

Answer:

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