Question

If the LCM of two numbers is 120 and their hcf is 4 find the possible values of two numbers

Answer 1

Answer:

We know that,

LCM(a,b) × HCF(a,b) = Product of numbers( a × b)

120 × 4 = a×b

= 480

Thus, 2 factors of 480 whose multiples form 480 will be the possible values of two numbers....

Please mark brainliest if it helped you

Answer 2

Answer:

According to the formula,

L.C.M x H.C.F=Product of two numbers

Given,

L.C.M of two numbers=120

H.C.F of two numbers=4

When we substitute the values of L.C.M and H.C.F in the formula, we get-

120x4=480

The product of the two numbers will be 480.

Since the H.C.F of two numbers is 4, they will be multiples of 4.

Let the numbers be 4x and 4y

Using the formula given above,

$4x$×$4y$=4x120

16$xy$=480

xy=30

The two numbers that are 4x and 4y will be divisible by 4 and x and y will be co-primes.

The possible pairs of x and y will be (5,6);(30,1);(15,2);(10,3).

So the possible values of the two numbers will be-

(4x5,4x6)=(20,24)

(4x30,4x1)=(120,1)

(4x15,4x2)=(60,8)

(4x10,4x3)=(40,12)

Learn more about L.C.M and H.C.F by clicking on the links given below-

https://brainly.in/question/20776338?referrer=searchResults

https://brainly.in/question/25945206?referrer=searchResults