if the LCM of two numbers is 216 and their product is 7776 what will be the HCF
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Answered by
1
Answer:
Let x and y be the numbers
27x+27y=216, x+y=8
The possible pairs are (1, 7) and (2, 6)
The Co. prime pairs is (1, 7)
The numbers are (27×1, 27×7)=27, 189
Step-by-step explanation:
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Answered by
1
Answer:
a × b = HCF × LCM
given product is 7776
now
7776 = 216 × HCF
7776/216 = HCF
HCF = 36
Step-by-step explanation:
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