If the least count of vernier caliper is 0.01 cm and least count of sphero meter is 0.001 cm then which will be the more accurate and why?
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Answer:
Correct option is
C
1.83
L.C. = 0.01 cm
Error = + 0.02 cm ⇒ Positive zero
error = + 0.02 cm
main scale reading (MSR) = 3.60 cm 8
th
vernier scale coincides with main scale
⇒ vernier coincidence (VC) = 8
We know that
Correct diameter = [main scale reading+ (L.C × V.C)] - (error)
= [3.60 + (0.01 × 8)] - [+ 0.002]
= (3.60 + 0.08)- (+0.02)
= 3.68 - 0.02
= 3.66 cm
∴correctradius=
2
diameter
=
2
3.66
=1.83cm
Explanation:
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