if the length and breadth of a rectangle are doubled, how many times the perimeter of the old rectangle will that of the new rectangle be?
Answers
Answered by
8
Hey☺
Let the length be l
and breadth be b
✴ Perimeter of rectangle = 2(l+b)
According to question ,
New breadth = 2b
New length =2l
✴ Perimeter of new rectangle =. 2(2l+2b)
= 4(l+b)
Since Perimeter of new rectangle is 4(l+b)
Their ratio would be
4(l+b) / 2(l+b)
✔✔2:1
Therefore the perimeter of new rectangle is double of that of old one
Let the length be l
and breadth be b
✴ Perimeter of rectangle = 2(l+b)
According to question ,
New breadth = 2b
New length =2l
✴ Perimeter of new rectangle =. 2(2l+2b)
= 4(l+b)
Since Perimeter of new rectangle is 4(l+b)
Their ratio would be
4(l+b) / 2(l+b)
✔✔2:1
Therefore the perimeter of new rectangle is double of that of old one
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Answered by
12
Hi...✌
Here is your answer...☺
Let the length and breath of old rectangle be L and B respectively.
Perimeter P = 2(L+B) ......(1)
_______________
If they are doubled
New length = 2L
New breath = 2B
Perimeter of new rectangle= 2(2L+2B)
= 2×2(L+B)
= 2×P ......( from (1) )
Hence,
Perimeter of new rectangle is the DOUBLE of the perimeter of old rectangle.
Thank you ⭐
Here is your answer...☺
Let the length and breath of old rectangle be L and B respectively.
Perimeter P = 2(L+B) ......(1)
_______________
If they are doubled
New length = 2L
New breath = 2B
Perimeter of new rectangle= 2(2L+2B)
= 2×2(L+B)
= 2×P ......( from (1) )
Hence,
Perimeter of new rectangle is the DOUBLE of the perimeter of old rectangle.
Thank you ⭐
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