If the length and breadth of a room are increased by 1m . The area of the room increased by 21 sq m . If the length is increased by 1m and breadth is decreased by 1m the area is decreased by 5 sq m . Find the perimeter of the room
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Let breadth be b and length be a.
So,
(a +1) (b + 1) = 21 + ab
ab + a + b + 1 = 21 + ab
a + b = 20
b = 20 - a
Now , we form the second equation;
( a + 1 ) (b - 1 ) = ab - 5
ab - a + b -1 = ab - 5
20 - a -a -1 = -5
-2a + 19 = -5
-2a = -19 - 5
a = -24 / -2 => a = 12
And, b = 20 - a = 20 - 12 = b = 8
Now using the formula for the perimeter;
2 ( l + b ) => 2 (a + b ) = > 2 * 8 * 12 = 192
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