if the length and breadth of an rectangle are (2x^2-5x+2) and (x^2-2x-4) respective ly find perimeter
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perimeter = 2(length + breadth)
so P = 2{(2x^2-5x+2) +(x^2-2x-4) }
= 2{(2x^2+x^2) +(-5x-2x) +(2-4) }
=2(3x^2-7x-2)
=6x^2-14x-4
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