if the length and breadth of the rectangular plot are increased by 50% and 20% respectively then you area will be how many times that of the original area
Answers
Answered by
49
LET THE ORIGINAL LENGTH BE L
AND
ORIGINAL BREATH BE B.
ORIGINAL AREA = LB
LENGTH INCREASED BY 50% = 150 L / 100
BREATH INCREASED BY 20% = 120 B / 100
INCREASED AREA = 150 L X 120 B / 100 X 100
= 18000 LB / 10000
= 1.8 LB
NOW,
1.8 LB / LB = 1.8
CHANGING 1.8 INTO FRACTION.
1.8 = 18/10 = 9/5
SO,
THE INCREASED AREA WILL BE 9/5 TIMES OF THE ORIGINAL AREA.
PLZ MARK IT AS BRAINLIEST ANSWER AND DROP A ♥
AND
ORIGINAL BREATH BE B.
ORIGINAL AREA = LB
LENGTH INCREASED BY 50% = 150 L / 100
BREATH INCREASED BY 20% = 120 B / 100
INCREASED AREA = 150 L X 120 B / 100 X 100
= 18000 LB / 10000
= 1.8 LB
NOW,
1.8 LB / LB = 1.8
CHANGING 1.8 INTO FRACTION.
1.8 = 18/10 = 9/5
SO,
THE INCREASED AREA WILL BE 9/5 TIMES OF THE ORIGINAL AREA.
PLZ MARK IT AS BRAINLIEST ANSWER AND DROP A ♥
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Answered by
10
Let the length of rectangle be x
and breadth be y
So Area= length×breadth
= x×y
According to The question
length = x+x×50%/100= x+1/2x=3x/2
breadth= y+y×20%/100=y+1/5y= 6y/5
New Area= 3x/2 × 6y/5
Compare both the areas
New Area= Original Area
9xy/5= xy
9xy=5xy
9xy/5xy=9/5
9/5 times area would be increase
and breadth be y
So Area= length×breadth
= x×y
According to The question
length = x+x×50%/100= x+1/2x=3x/2
breadth= y+y×20%/100=y+1/5y= 6y/5
New Area= 3x/2 × 6y/5
Compare both the areas
New Area= Original Area
9xy/5= xy
9xy=5xy
9xy/5xy=9/5
9/5 times area would be increase
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