Math, asked by AnonAsks, 1 month ago

If the length and the breadth of a rectangle are each increased by 1 metre, the area of the rectangle is increased by 22 square metres. If the length is decreased by 2 metres and the breadth is increased by 3 metres, the area is increased by 12 square metres. Find the perimeter of the rectangle.

Answers

Answered by s14975apratibha07847
1

Answer:

the length and the breadth of a rectangle are each increased by 1 metre, the area of the rectangle is increased by 22 square metres. If the length is decreased by 2 metres and the breadth is increased by 3 metres, the area is increased by 12 square metres. Find the perimeter of the rectangle.

Step-by-step explanation:

hi

Answered by Kuku01
2

Step-by-step explanation:

let the length and breadth of room be l and b respectively

area of room=lb

after increasing length by 1m=(l+1)

after increasing breadth by 1m=(b+1)

now, according to the question,

(l+1)(b+1)=lb+21

(l+1)(b+1)−lb=21

l+b=20⟶(1)

When, length increased by 1m and breadth is decreased by 1m, then

lb−[(l+1)(b−1)]=5

l−b=6⟶(2)

solving (1) & (2), we get

l=13 and b=7

∴ perimeter=2(l+b)m=2(13+7)=40m

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