If the length and time period of an oscillating pendulum have error of 1% and 3% respectively then the error in measurement of asseleration due to gravity is
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Answer:
We know,
Time period, =2π√(l/g)
Taking square both sides,
T square =4π square l/g = 4π square l/T Square
so, for finding error in accelerating due to gravity we have to take formula,
% error in g=% eeror l+2x% error in T
Given,
% error in l = 1%
% error in T = 3%
:- %error in g = 1% + 2x3% = 7%
Hence answer is 7%.
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Explanation:
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