Question

if the length, breath and height of a wall is given L-14feet, B-10feet and H-10feet. what is the area of the wall

Answer 1

SURFACE AREA OF THE WALL=
2(LB+BH+LH) AS THE WALL IS A CUBOID

LENGTH=14 FEET
BREADTH=10 FEET
HEIGHT=10 FEET

= 2 X (14 X 10 + 10 X 10 +14 X 10)
=2 X 380
=760

LATERAL SURFACE AREA=
2 X (L + B) X H

=2 X (14 + 10) X 10
=2 X 240
=480

AREA OF WALL =
L X B
=14 X 10
=140

VOLUME OF WALL=
L X B X H
=14 X 10 X 10
=1400

Answer 2

l
the wall is in shape of cuboid
length=14feet 
breath=10feet
height=10feet
surface area= 2(lb+bh+hl)
 2 X (14 X 10 + 10 X 10 +14 X 10)
=2 X 380
=760

Lateral surface area=
2 X (L + B) X H

=2 X (14 + 10) X 10
=2 X 240
=480

Area of wall =
L X B
=14 X 10
=140

Volume of wall=
L X B X H
=14 X 10 X 10
=1400