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1) The constant polynomial
2)(i) Let us assume the division of 6x2 + 2x + 2 by 2
Here, p(x) = 6x2 + 2x + 2
g(x) = 2
q(x) = 3x2 + x + 1
r(x) = 0
Degree of p(x) and q(x) is same i.e. 2.
Checking for division algorithm,
p(x) = g(x) × q(x) + r(x)
Or, 6x2 + 2x + 2 = 2x (3x2 + x + 1)
Hence, division algorithm is satisfied.
(ii) Let us assume the division of x3+ x by x2,
Here, p(x) = x3 + x
g(x) = x2
q(x) = x and r(x) = x
Clearly, the degree of q(x) and r(x) is the same i.e., 1.
Checking for division algorithm,
p(x) = g(x) × q(x) + r(x)
x3 + x = (x2 ) × x + x
x3 + x = x3 + x
Thus, the division algorithm is satisfied.
(iii) Let us assume the division of x3+ 1 by x2.
Here, p(x) = x3 + 1
g(x) = x2
q(x) = x and r(x) = 1
Clearly, the degree of r(x) is 0.
Checking for division algorithm,
p(x) = g(x) × q(x) + r(x)
x3 + 1 = (x2 ) × x + 1
x3 + 1 = x3 + 1
Thus, the division algorithm is satisfied.
3)real number
4)X - 1 is a factor of 4x^3 + 3x^2 -4x +k
then x=1 is one root of 4x^3 + 3x^2 -4x +k
put x= 1
4x^3 +3x^2 -4x +k = 0
=> 4 (1)^3 +3 (1)^2-4 (1) +k =0
=> 4 + 3 - 4 + k = 0
=> k = -3
5)Trinomial
6)The degree of the polynomial is zero. Because root 2can be written as root root 2x so x0, and the highest power of x of this polynomial is zero
7)Remainder is 50
8)it has no degree
9)3
10)Third degree polynomials are also known as cubic polynomials. Cubics have these characteristics: One to three roots. Two or zero extrema.
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