Question

If the length is 25cm and breadth is twice its length. What is perimeter of a rectangle ?

Answer 1

sorry for the bad handwriting ...

Answer 2

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Given:}}}}}}}\end{gathered}$

• ● The length of a Rectangle is 25 cm and breadth is twice its length.

$\begin{gathered} \end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{To Find:}}}}}}}\end{gathered}$

• ● Perimeter of Rectangle

$\begin{gathered} \end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Using Formula:}}}}}}}\end{gathered}$

$\dag{\underline{\boxed{\sf{Perimeter \: of \: Rectangle = 2 \big\{Length + Breadth \big\}}}}}$

$\begin{gathered} \end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Solution:}}}}}}}\end{gathered}$

$\bigstar \: {\underline{\pmb{\frak{\red{Here..}}}}}$

• $\dashrightarrow{\sf{Length = 25 \: cm}}$
• $\dashrightarrow\sf{Breadth = 25 \times 2 = 50 \: cm}$

$\bigstar \: \underline {\pmb{\frak\red{Finding \: the \: Perimeter..}}}$

$\quad{: \implies{\sf{Perimeter \: of \: Rectangle = \bf{2 \big\{Length + Breadth \big\}}}}}$

• Substituting the values

$\quad{: \implies{\sf{Perimeter \: of \: Rectangle = \bf{2 \big\{25 + 50\big\}}}}}$

$\quad{: \implies{\sf{Perimeter \: of \: Rectangle = \bf{2 \big\{75 \: cm\big\}}}}}$

$\quad{: \implies{\sf{Perimeter \: of \: Rectangle = \bf{2 \times 75 \: cm}}}}$

$\quad{: \implies{\sf{Perimeter \: of \: Rectangle = \bf{150 \: cm}}}}$

$\begin{gathered} \dag{\overline{\underline{\boxed{\textsf{\textbf{\color{red}{Perimeter \: of \: Rectangle = 150 \: cm}}}}}}}\end{gathered}$

Hence, The Perimeter of Rectangle is 150 cm

$\begin{gathered} \end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Diagram:}}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\tiny\begin{gathered} {\begin{gathered} \sf{25 \:cm}\huge\boxed{ \begin{array}{cc} \: \: \: {\tiny{\sf{LoveYouHindi}}} \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \end{array}} \\ \: \: \: \: \: \sf{50 \: cm} \end{gathered}}\end{gathered}\end{gathered}\end{gathered}$

• ● Length = 25 cm
• ● Breadth = 50 cm

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 50 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 25 cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}$

• ● Request: Please see the answer from website Brainly.in
• ● Check the given attachment also!!

$\begin{gathered} \end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Learn More:}}}}}}}\end{gathered}$

$\begin{gathered}\small\begin{gathered}\bigstar \: \bf\underline{More \: Useful \: Formulae } \: \bigstar  \\ \begin{gathered}{\boxed{\begin{array} {cccc}{\sf{{\leadsto TSA \: of \: cube \: = \: 6(side)^{2}}}} \\  \\ {\sf{{\leadsto LSA \: of \: cube \:= \: 4(side)^{2}}}}  \\  \\{\sf{{\leadsto Volume \: of \: cube \: = \: (side)^{3}}}} \\  \\ {\sf{{\leadsto Diagonal \: of \: cube \: = \: \sqrt(l^{2} + b^{2} + h^{2})}}} \\  \\ {\sf{{\leadsto Perimeter \: of \: cube \: = \: 4(l+b+h)}}} \\   \\ {\sf{{\leadsto CSA \: of \: sphere \: = \: 2 \pi r^{2}}}} \\  \\ {\sf{{\leadsto SA \: of \: sphere \: = \: 4 \pi r^{2}}}} \\  \\{\sf{{\leadsto TSA \: of \: sphere \: = \: 3 \pi r^{2}}}} \\  \\ {\sf{{\leadsto Diameter \: of \: circle \: = \: 2r}}} \\  \\ {\sf{{\leadsto Radius \: of \: circle \: = \: \dfrac{d}{2}}}} \\  \\ {\sf{{\leadsto Volume \: of \: sphere \: = \: \dfrac{4}{3} \pi r^{3}}}} \\  \\ {\sf{{\leadsto Area \: of \: rectangle \: = \: Length \times Breadth}}} \\  \\ {\sf{{\leadsto Perimeter \: of \: rectangle \: = \:2(length+breadth)}}} \\  \\{\sf{{\leadsto Perimeter \: of \: square \: = \: 4 \times sides}}}\end{array}}}\end{gathered}\end{gathered}\end{gathered}$