Math, asked by HardikTomar, 9 months ago

if the length is twice than the breath and the area is 666m than find the length and breath​

Answers

Answered by Truebrainlian9899
69

\rightarrow Given :

  • Length = 2 × breadth

  • Area = 666m

\rightarrow To Find :

  • Length

  • Breadth

  \huge \red{ \underline{ \underline{ \green{{ \rm \: solution : }}}}}

  • Let bradth be = x

\therefore length = 2x

 \rightarrow  \pink{ \boxed{ \boxed{ \purple{ \rm \: area = length \times breadth}}}}

\implies 666m = 2x × x

 \implies \rm \: \mathtt{ 666m = 2x {}^{2} }

  • On transposing the terms :

 \implies \mathtt{ \dfrac{666m}{2} =  {x}^{2}  }

 \implies \rm \:  \orange{\mathtt{333m = x {}^{2} }}

 \implies \rm \: \mathtt{ \sqrt{333} = x {}^{} }

 \large \therefore { \blue{ \boxed{ \red{ \rm \: x = 18.24m}}}}

 \rightarrow \purple{ \rm \:breadth = x =  \green{ \boxed{ \pink{18.24 \rm m}}}}

\purple{ \rm  \: length = 2x =  2 \times 18.24 = \green{ \boxed{ \pink{36.48 \rm m}}}}

Answered by SɴᴏᴡʏSᴇᴄʀᴇᴛ
35

\huge\boxed{\underline{\sf{\red{ᴀ}\green{ɴ}\pink{s}\orange{ᴡ}\blue{ᴇ}\pink{ʀ}}}}

\underline{\sf{Length\:=\:36.48m}}

\underline{\sf{Breadth\:=\:18.24m}}

\bold{\boxed{\sf{\red{Given;}}}}

\sf{Length\:is\:twice\:it's\:breadth}

\sf{Area\:of\:it\:=\:666m}

\bold{\boxed{\sf{\red{To\:Find}}}}

\sf{Length\:and\:breadth}

\bold{\boxed{\sf{\red{Solution;}}}}

\sf{Let\:x\:be\:it's\:breadth}

\sf{Length\:=\:2x}

\longrightarrow{\boxed{\boxed{\sf{\purple{Area\:=\:Length\:×\:Breadth}}}}}

\rightarrow{\sf{666m\:=\:2x\:×\:x}}

\rightarrow{\sf{666m\:=\:2x^{2}}}

\rightarrow{\sf{\frac{666m}{2}\:=\:x^{2}}}

\rightarrow{\sf{333\:=\:x^{2}}}

\rightarrow{\sf{\sqrt{333}\:=\:x}}

\sf{Therefore;}

\longrightarrow{\boxed{\boxed{\sf{\pink{18.24m\:=\:Breadth}}}}}

\longrightarrow{\boxed{\boxed{\sf{\pink{36.47m\:=\:Length}}}}}

\bold{\sf{Thus\:Proved...}}

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