Question

if the length is twice the breadth and the perimeter and are are numerically equal than find area of rectangle if the 1/3 perimeter is equals to 64​

Answer 1

Answer:

hii

Step-by-step explanation:

b-x

l-2x

1/3 of perimeter = 64

let perimeter be p

1/3 *p = 64

p= 64*3=192

2(l+b)=192

2(2x+x)

4x+2x=6x

6x=192

x=192/6 =>32

l=64

b=32

area=l*b

64*32 =2048