If the length L of a rectangle is 3 meters more than twice its width and its perimeter is 300 meters, which of the following equations could be used to find L?
Answers
Answered by
0
given:-
l=3m more than twice it's width i.e.,3+2b
then let width be b
perimeter=300m
according to the question:-
perimeter of the rectangle=2(l+b)
or, 300m=2(3+2b)
or,. 300/2= 3+2b
or,. 150 - 3= 2b
or,. 147=2b
therefore ,. length=3m+2b
length=3m+147=150m
l=3m more than twice it's width i.e.,3+2b
then let width be b
perimeter=300m
according to the question:-
perimeter of the rectangle=2(l+b)
or, 300m=2(3+2b)
or,. 300/2= 3+2b
or,. 150 - 3= 2b
or,. 147=2b
therefore ,. length=3m+2b
length=3m+147=150m
Similar questions