if the length of a certain rectamgle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectagle would result. find the perimeter of the original rectangle
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Let x and y be the length and breadth of the rectangle respectively. Then, x - 4 = y + 3 or x - y = 7 ----(i) Area of the rectangle =xy; Area of the square = (x - 4) (y + 3) (x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii) Solving (i) and (ii), we get x = 16 and y = 9. Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.Read more on Sarthaks.com - https://www.sarthaks.com/449882/if-the-length-of-a-certain-rectangle-is-decreased-by-4-cm-and-the-width-is-increased-by-3-cm
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