Physics, asked by pragati6666, 3 months ago

Example 12.13
An electric refrigerator rated 400 W operates 8 hour/day. What is
the cost of the energy to operate it for 30 days at Rs 3.00 per kW h?​

Answers

Answered by safras
4

Explanation:

Energy of one day =Power×Time=400W×8h=3.2KWh

Energy of 30 days =3.2KWh×30=96KWh

So, cost of the energy =96×3=Rs.288

I hope it help you

Similar questions